Test Series - computer fundamental

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Test Number 22/95

Q: Boolean Function is of the form of ________
A. Truth values
B. K=f(X,Y,X)
C. Algebraic Expression
D. Truth Table
Solution: The boolean function is of the form of algebraic expressions or truth table. A boolean function is of the form as that of option 2. The result obtained from a boolean function can be a truth value or a fallacy.
Q: The result of X+X.Y is X.
A. True
B. False
C. 0
D. none
Solution: This is a boolean expression. It can be evaluated as :
X+X.Y = X(1+Y) = X.
Since 1+Y=1 by boolean laws.
Q: In the boolean function w=f(X,Y,Z), what is the RHS referred to as ________
A. right hand side
B. expression
C. literals
D. boolean
Solution: The RHS is commonly referred to as the expression. The symbols X, Y and Z are commonly referred to as the literals of the function.
Q: The general form for calculating the number of rows in a truth table is ________
A. 2n
B. 2n+1
C. 2n
D. 2n+1
Solution: The general form for the calculation of rows in a truth table is 2n . Here, n= number of literals in the function.
Q: The number of literals in the expression F=X.Y’ + Z are _____________
A. 4
B. 3
C. 2
D. 1
Solution: Literals the generally the number of variables used in any boolean expression. Here, since there are 3 variables X, Y and Z, therefore the answer is 3.
Q: The complement term for X’.Y’.Z + X.Y will be _____________
A. XYZ’+X’Y’
B. (X+Y+Z’)(X’+Y’)
C. (X+Y+Z’)(X’+Y)
D. (X+Y+Z’)(X’+Y)
Solution: The OR and AND operators are interchanged. The complement terms are reduced to normal terms and the result is obtained.
Q: What is the complement of X’Y’Z?
A. X+YZ
B. X’+Y+’Z’
C. X+Y+Z’
D. XYZ’
Solution: The complement is obtained by converting the complement terms to normal terms and vice versa. Also, the OR and AND operators are interchanged. Here, X’Y’Z gets converted to X+Y+Z’.
Q: The minterm of any expression is denoted by ___________
A. Mt
B. m
C. M
D. min
Solution: The variables forming an AND term is generally the minterm. It is denoted by m. (lower case letter).
Q: The min term when X=Y=Z=0 is _____________
A. x’+y’+z’
B. xyz
C. x’y’z’
D. x+y+z
Solution: There minterm expression is obtained using the AND term. Here, when X=Y=Z=0, the expression obtained is x’y’z’.
Q: The max term when X=Y=Z=1 is ________
A. x’+y’+z’
B. xyz
C. x’y’z’
D. x+y+z
Solution: The max term consists of variables forming an OR term. Here, when X=Y=Z=1, the expression is x’+y’+z’.

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